Вычислите: √3-2√2·√3+2√2

[latex] \sqrt{3-2 \sqrt{2}}- \sqrt{3+2 \sqrt{2}}= \sqrt{( \sqrt{2}-1)^2 }- \sqrt{( \sqrt{2}+1)^2} = \\ \sqrt{2}-1- \sqrt{2} -1=-2  [/latex]