Вычислите t²(180°+α)·sin²(90°+α) , если a=π/3

[latex]tg^2(180^\circ + \alpha )*sin^2(90^\circ + \alpha )=tg^2 \alpha *cos^2 \alpha = \frac{sin^2 \alpha }{cos^2 \alpha }*cos^2 \alpha =sin^2 \alpha [/latex] [latex] \alpha = \frac{ \pi }{3} [/latex] [latex]sin^2 \alpha =sin^2 \frac{ \pi }{3} =( \frac{ \sqrt{3} }{2} )^2= \frac{3}{4} [/latex]