Вычислите значение дроби 3a-5b/2a-3b если 5a-4b=0

5a - 4b = 0 => 5a = 4b => [latex] \frac{a}{b} = \frac{4}{5} [/latex] [latex] \dfrac{3a-5b}{2a-3b} = \dfrac{b(3 \frac{a}{b}-5) }{b(2 \frac{a}{b}-3) } =\dfrac{3* \frac{a}{b}-5 }{2* \frac{a}{b}-3 } =\dfrac{3* \frac{4}{5}-5}{{2* \frac{4}{5}-3}}=\dfrac{12-25}{8-15}=\dfrac{13}{7}[/latex]