(x-1)в кубе + (x-2)в кубе = 2x - 3

(x-1)³+(x-2)³=2x-3 x³-3x²+3x-1+x³-6x²+12x-8-2x+3=0 2x³-9x²+13x-6=0 x₁=1 2x³-9x²+13x-6   |_x-1_ 2x³-2x²               | 2x²-7x+6 ---------       -7x²+13x       -7x²+7x       -----------                 6x-6                 6x-6                 ------                        0 2x²-7x+6=0   D=1 x₂=2     x₃=1,5 Ответ:  x₁=1       x₂=2       x₃=1,5.