x-3 - 3-y xy-[latex] x^{2} [/latex] xy-[latex] y^{2} [/latex]
x-3 - 3-y
xy-[latex] x^{2} [/latex] xy-[latex] y^{2} [/latex]
Ответ(ы) на вопрос:
[latex]= \frac{x-3}{x(y-x)}- \frac{3-y}{y(x-y)} = \frac{-y(x-3)-x(3-y)}{xy(x-y)}= \frac{-xy+3y-3x+xy}{xy(x-y)}= \\ = \frac{3(y-x)}{xy(x-y)} = \frac{-3}{xy} [/latex]
Не нашли ответ?
Похожие вопросы