(x+14)^2=56 Буду благодарна за помощь

(x+14)²=56 x²+2*14*x+14²=56 x²+28x+196-56=0 x²+28x+140=0 D=28²-140*4=784-560=224 x₁=(-28+√224)/2=(-28+4√14)/2=-14+2√14 x₂=(-28-√224)/2=(-28-4√14)/2=-14-2√14

[latex]( x+14) ^{2} = 56[/latex] [latex] x^{2} + 28x + 196 = 56 [/latex] [latex] x^{2} +28x + 140 = 0[/latex] [latex]D = (28^{2}) - 4*1*140 = 784 - 560 = 224 [/latex] [latex] \sqrt{D} = \sqrt{224} = 2\sqrt{56}[/latex] [latex]x1 = \frac{-28 - \sqrt{224} }{2} = -2\sqrt{14} - 14[/latex] [latex]x2 = \frac{-28 + \sqrt{224} }{2} = 2\sqrt{14} -14[/latex]