X^2-24x=-22x+24-x^2 Решите

[latex] x^{2} -24x=-22x+24- x^{2} \\ x^{2} + x^{2} -24x+22x-24=0 \\ 2 x^{2} -2x-24=0 \\ x^{2} -x-12=0 \\ D=(-1) ^{2} -4*(-12)=1+48=49= 7^{2} \\ x_{1} = \frac{1+7}{2} =4 \\ x_{2} = \frac{1-7}{2} =-3 \\ [/latex] Ответ: х₁ = 4; х₂ = - 3.