X^2y+xy^2=6 xy+x+y=3 (система)

[latex] \left \{ {{x^2y+xy^2=6} \atop {xy+x+y=3}} \right. ; \left \{ {{xy(x+y)=6} \atop {xy=3-(x+y)}} \right.; \left \{ {{xy=\frac{6}{x+y}} \atop {xy=3-(x+y)}} \right.[/latex] Замена xy = a, x + y = b [latex]\left \{ {{ab=6} \atop {a=3-b}} \right. \\(3-b)b=6\\ b^2-3b+6 = 0;\\D < 0 [/latex] Решений нет