(x+3)(x-4)=-12 (3x-1)^2=1 (2x+3)(3x+1)=11x+30 18-(x-5)(x-4)=-2 5x+(2x+1)(x-3)=0 x^2-5=(x-5)(2x-1) через дискриминант

Решение 1)  (x+3)(x-4)=-12 x² - x - 12 = - 12 x(x - 1) = 0 x₁ = 0 x₂ = 1 Ответ: х₁ = 0 : х₂ = 1 2)  (3x-1)^2=1 3x - 1 = - 1 3x = 0  x₁ = 0 3x - 1 = 1  3x = 2 x₂ =  2/3  Ответ: х₁ = 0; х₂ = 2/3 3)  (2x+3)(3x+1)=11x+30 6x² + 11x + 3 = 11x + 30 6x² = 27 x² = 9/2 x₁ = - 3√2/2 x₂ = 3√2/2 Ответ: x₁ = - 3√2/2; x₂ = 3√2/2 4)  18-(x-5)(x-4)=-2 x² - 9x + 20 = 20 x(x - 9) = 0 x₁ = 0 x₂ = 9 Ответ: x₁ = 0 ; x₂ = 9 5)  5x+(2x+1)(x-3)=0 5x + 2x² - 5x - 3 = 0 2x² - 3 = 0 2x² = 3 x² = 3/2 x₁ = - √6/3 x₂ = √6/3 6)  x^2-5=(x-5)(2x-1) x² - 5 = 2x² - 11x + 5 x² - 11x + 10 = 0 x₁ = 1 x₂ = 10 Ответ: x₁ = 1 ; x₂ = 10