Y=(x^2+4)^2/(x+3) производная

[latex]y' = \frac{2(x^2+4)*2x*(x+3)-(x^2+4)^2}{(x+3)^2}= \frac{4x(x^2+4)(x+3)-(x^2+4)^2}{(x+3)^2}= \\ \\ = \frac{4x(x^3+4x+3x^2+12)-(x^4+8x^2+16)}{(x+3)^2}= \\ \\  [latex]= \frac{4x^4+16x^2+12x^3+48x-x^4-8x^2-16}{(x+3)^2}= \\ \\ = \frac{3x^4+12x^3+8x^2+48x-16}{(x+3)^2} [/latex]