Z1=2+5i z2=1-i Найти z1+z2; z1-z2; z1:z2;z1*z2

[latex]z_1+z_2=2+5i+1-i=(2+1)+(5-1)i=3+4i[/latex] [latex]z_1-z_2=2+5i-1+i=(2-1)+(5+1)i=1+6i[/latex] [latex]z_1:z_2= \frac{2\cdot 1+5\cdot (-1)}{1^2+(-1)^2} +(\frac{5\cdot 1+2}{1^2+(-1)^2} )i=-1.5+3.5i[/latex] [latex]z_1\cdot z_2=(2\cdot1-5\cdot (-1))+(5\cdot 1+2\cdot(-1))i=7+3i[/latex]