Задача 45 пожалуйста

[latex]x^2+x-3=|2x-1|\\\\a)\; \; 2x-1 \geq 0\; ,\; \; x \geq \frac{1}{2}\; ,\; \; |2x-1|=2x-1\\\\x^2+x-3=2x-1\\\\x^2-x-2=0\\\\x_1=-1\ \textless \ \frac{1}{2}\; (ne\; podxodit)\\\\\boxed {x_2=2}\\\\b)\; \; 2x-1\ \textless \ 0\; ,\; x\ \textless \ \frac{1}{2}\; ,\; \; |2x-1|=1-2x\\\\x^2+x-3=1-2x\\\\x^2+3x-4=0\\\\x_1=1\ \textgreater \ \frac{1}{2}\; \; (ne\; podxodit)\\\\\boxed {x_2=-4}\\\\c)\; \; \; x_1\cdot x_2=2\cdot (-4)=-8[/latex]