Запишите приведённое квадратное уравнение 1) x1=5 и X2=-3 2) x1=-10 и X2=-6

1) (х-5)(х+3) = х²+3х-5х-15 = х²-2х-15 D = 4+60 = 64 = 8² х₁ = [latex] \frac{2+8}{2} [/latex] = [latex] \frac{10}{2} [/latex] = 5 х₂ = [latex] \frac{2-8}{2} [/latex] = [latex] \frac{-6}{2} [/latex] = -3 2)(х+10)(х+6) = х²+6х+10х+60 = х²+16х+60 D = 256-240 = 16 х₁ = [latex] \frac{-16+4}{2} [/latex] = [latex] \frac{-12}{2} [/latex] = -6 х₂ = [latex] \frac{-16-4}{2} [/latex] = [latex] \frac{-20}{2} [/latex] = -10