Здравствуйте! Помогите, пожалуйста, решить 112 и 114.

[latex]112\\ sin(x+\frac{\pi}{6})+cos(x+\frac{\pi}{3})=\frac{\sqrt3}{2}\\sinxcos\frac{\pi}{6}+cosxsin\frac{\pi}{6}+cosxcos\frac{\pi}{3}-sinxsin\frac{\pi}{3}=\frac{\sqrt3}{2}\\\frac{\sqrt3}{2}sinx+\frac{1}{2}cosx+\frac{1}{2}cosx-\frac{\sqrt3}{2}sinx=\frac{\sqrt3}{2}\\cosx=\frac{\sqrt3}{2}\\x=\pm arccos\frac{\sqrt3}{2}+2\pi n\\x=\pm \frac{\pi}{6}+2\pi n, \; n\in Z;[/latex] [latex]114\\ sin3x+cos11x=0\\sin3x+sin(\frac{\pi}{2}-11x)=0\\2sin\frac{3x+\frac{\pi}{2}-11x}{2}cos\frac{3x-\frac{\pi}{2}+11x}{2}=0\\sin(\frac{\pi}{4}-4x)cos(7x-\frac{\pi}{4})=0\\\\sin(4x-\frac{\pi}{4})=0\\4x-\frac{\pi}{4}=\pi n\\4x=\frac{\pi}{4}+\pi n\\x=\frac{\pi}{16}+\frac{\pi n}{4}, \; n\in Z;\\\\cos(7x-\frac{\pi}{4})=0\\7x-\frac{\pi}{4}=\frac{\pi}{2}+\pi n\\7x=\frac{\pi}{2}+\frac{\pi}{4}+\pi n\\x=\frac{3\pi}{28}+\frac{\pi n}{7}, \; n\in Z.[/latex]