1) sin180-cos90°= ?2)[latex] \sqrt{3} [/latex]tg30°-cos60°= ?3) cos45°+[latex] \sqrt{3}.[latex]sin60°=?4) sin(-45°)+3cos(-45°)=?5)[latex] \sqrt{6}[/latex] /3tg405°sin(-60°)*cos(-45°)=?6) sin [latex]\frac{ \pi}{2}[/latex] -...

Question

1) sin180-cos90°= ?2)[latex] \sqrt{3} [/latex]tg30°-cos60°= ?3) cos45°+[latex] \sqrt{3}.[latex]sin60°=?4) sin(-45°)+3cos(-45°)=?5)[latex] \sqrt{6}[/latex] /3tg405°sin(-60°)*cos(-45°)=?6) sin [latex]\frac{ \pi}{2}[/latex] -...

1) sin180-cos90°= ? 2)[latex] \sqrt{3} [/latex]*tg30°-cos60°= ? 3) cos45°+[latex] \sqrt{3}.[latex]*sin60°=? 4) sin(-45°)+3cos(-45°)=? 5)[latex] \sqrt{6}[/latex] /3*tg405°*sin(-60°)*cos(-45°)=? 6) sin [latex]\frac{ \pi}{2}[/latex] -cos \frac{ 3 \pi }{2}=? 7) tg[latex] \pi [/latex]+cos \pi =? 8) cos(- [latex]\pi[/latex] )+sin [latex]\frac{ \pi }{2[/latex]}=?

Гость

Ответ(ы) на вопрос:

Accepted Answer

sin(180) - cos(90) = 0 - 0 = 0. (т. к. sin(180) = 0; cos(90) = 0.).

1) sin180-cos90°= ?2)[latex] \sqrt{3} [/latex]*tg30°-cos60°= ?3) cos45°+[latex] \sqrt{3}.[latex]*sin60°=?4) sin(-45°)+3cos(-45°)=?5)[latex] \sqrt{6}[/latex] /3*tg405°*sin(-60°)*cos(-45°)=?6) sin [latex]\frac{ \pi}{2}[/latex] -...

1) sin180-cos90°= ?2)[latex] \sqrt{3} [/latex]tg30°-cos60°= ?3) cos45°+[latex] \sqrt{3}.[latex]sin60°=?4) sin(-45°)+3cos(-45°)=?5)[latex] \sqrt{6}[/latex] /3tg405°sin(-60°)*cos(-45°)=?6) sin [latex]\frac{ \pi}{2}[/latex] -...