10-2^(3*x+1)=16/2^(3*x+1)

[latex]10-2^{3*x+1}=\frac{16}{2^{3*x+1}}\ ;2^{3*x+1}=a\\10-a=\frac{16}{a}|*a\\10a-a^2=16\\a^2-10a+16=0\\a_1=2\ \ \ \ \ \ \ \ \ \ \ ;a_2=8\\2^{3*x+1}=2\ \ \ \ \ \ 2^{3*x+1}=8\\3*x+1=1\ \ \ 2^{3*x+1}=2^3\\x=0\ \ \ \ \ \ \ \ \ \ \ \ \ \ 3*x+1=3\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=\frac{2}{3}[/latex]