10ав-(-5а+в)кв при а =√9 в=√5

[latex]10ab-(-5a+b)^{2} =[/latex] [latex]=10ab-(b-5a)^{2}=[/latex] [latex]=10ab-(b^{2}-2*b*5a+(5a)^{2})=[/latex] [latex]=10ab-(b^{2}-10ab+25a^{2})=[/latex] [latex]=10ab-b^{2}+10ab-25a^{2}=[/latex] [latex]=-25a^{2}-b^{2}+20ab=[/latex] [latex]=-25* (\sqrt{9})^{2} -(\sqrt{5})^{2}+ \sqrt{9}* \sqrt{5}=[/latex] [latex]=-25*9-5+ \sqrt{45}=[/latex] [latex]= 225-5+3 \sqrt{5}=[/latex] [latex]=220+3 \sqrt{5}[/latex] Успехов в учебе! Будут вопросы, пиши!