1.√3cosx-sinx=√22.соsx-√3sinx=2cos5x3. sin3x cos2x= sin5x4.sinx sin7x=sin3x sin5xhellp me , please

1 2(√3/2cosx-1/2sinx)=√2 cos(x+π/6)=√2/2 x+π/6=-π/4+2πn U x+π/6=π/4+2πn x=-5π/12+2πn U x=π/12+2πn,n∈z 2 2(1/2cosx-√3/2sinx)=2cos5x cos(x+π/3)=cos5x 5x=x+π/3+2πn U 5x=-π/3-x+2πn 4x=π/3+2πn U 6x=-π/3+2πn x=π/12+πn/2 U x=-π/18+πn/3,n∈z 3 sin3xcos2x=sin(3x+2x) sin3xcos2x=sin3xcos2x+sin2xcos3x sin2xcos3x=0 sin2x=0⇒2x=πn⇒x=πn/2,n∈z cos3x=0⇒3x=π/2+πn⇒x=π/6+πn/3,n∈z 4 sinxsin7x=sin3xsin5x 1/2[cos(7x-x)-cos(7x+x)]=1/2[cos(5x-3x)-cos(5x+3x)] cos6x-cos8x=cos2x-cos8x cos6x=cos2x 6x=2x+2πn U 6x=-2x+2πn 4x=2πn U 8x=2πn x=πn/2 U x=πn/4-общий