1,6 cosx + 1, 6 = 0 tg 3x = 1 2cos x + корень из трех = 0

[latex]1.6cos x+1.6=0[/latex] [latex]cos x+1=0[/latex] [latex]cos x=-1[/latex] [latex]x=-\pi+2*\pi*k[/latex] k є Z =========================== [latex]tg(3x)=1[/latex] [latex](3x)=\frac{\pi}{4}+\pi*k[/latex] [latex]x=\frac{\pi}{12}+\frac{\pi*k}{3}[/latex] k є Z =========================== [latex]2cos x+\sqrt{3}=0[/latex] [latex]cos x=-\frac{\sqrt{3}}{2}[/latex] [latex]x=^+_-(\pi-\frac{\pi}{6})+2*\pi*k[/latex] [latex]x=^+_-\frac{5\pi}{6}+2*\pi*k[/latex] k є Z