Ответ(ы) на вопрос:
[latex] \left \{ {{x^{2} - y^{2} -5xy=-6} \atop {x+y=3}} \right. \left \{ {{(3-y)^{2}-y^{2}-5y \cdot (3-y) +6=0} \atop {x=3-y}} \right. \\ \left \{ {{{9 -6y+y^{2}-y^{2}-15y+5y^{2}+6=0} \atop {x=3-y}} \right. \left \{ {{5y^{2}-21y+15=0} \atop {x=3-y}} \right. \\ 5y^{2}-21y+15=0 \\ y_{1,2}= \frac{21 \pm \sqrt{441 - 300} }{10}= \frac{21 \pm \sqrt{141} }{10} \; \left {{y_{1}=\frac{21 + \sqrt{141} }{10}} \atop {y_{2}=\frac{21 - \sqrt{141} }{10}}} \right. [/latex]
[latex]x_{1}=3 - \frac{21 + \sqrt{141} }{10}}, \; x_{2}=3 - \frac{21 - \sqrt{141} }{10}}} \\ x_{1}= \frac{9 - \sqrt{141} }{10}}, \; x_{2}=\frac{9 + \sqrt{141} }{10}}}[/latex]
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