25^2 - 23^2 / 35^2 - 29^2

по формуле разности квадратов 25^2 - 23^2 / 35^2 - 29^2=[latex] \frac{(25-23)(25+23)}{(35-29)(35+29)} = \frac{2*48}{6*64} = \frac{8}{32} = \frac{1}{4} [/latex]

25^2=625 23^2=529 35^2=1225 29^2=841 625-529/1225-841 529/1225~0,432 525-0,432-841=-316, 432