(2х-1)^2=2х-1 решите уравнение

(2X-1)²=2X-1 4x²-4x+1-2x+1=0 4x²-6x+2=0 2(2x²-3+1)=0 2x²-3+1=0 D=3²-4*1*2=9-8=1 [latex]x_{1}= \frac{-(-3)- \sqrt{1} }{2*2} = \frac{3-1}{4} = \frac{2}{4} =0.5 \\ x_{2}= \frac{-(-3)+ \sqrt{1} }{2*2} = \frac{3+1}{4} = \frac{4}{4} =1[/latex]