3*3^2x-7*12^x+4*4^2x=0

3*3^2x - 7*4^x*3^x +4*4^2x = 0 ! /3^2x 3*3^2x/3^2x - 7*4^x*3^x^/3^2x + 4*4^2x/3^2x = 0 3 - 7*(4/3)^x + 4*(4/3)^2x = 0 нехай (4/3)^х = t, (4/3)^2x = t^2 3-7t+4t^2 = 0 abo 4t^2 - 7t +3 = 0 a=4 b= -7 c=3 D= 49 - 48 = 1 t1 = 7+1/2*4=8/8=1 t2=7-1/2*4=6/8=3/4 1) t1=1 (4/3)^x=1 x=0 2) t2=(3/4) (4/3)^x=3/4 x=-1 Відповідь: -1, 0