(3/5)^-8*(5/3)^-6-3^-11(1/3)^-9 Помогите решить

[latex]( \frac{3}{5} )^{-8}*( \frac{5}{3})^{-6}-3^{-11}*( \frac{1}{3} )^{-9}=\frac{5^{8}}{3^{8}} *\frac{3^{6}}{5^{6}}- \frac{1}{3^{11}} *3^{9}=\frac{5^{8-6}}{3^{8-6}} - \frac{1}{3^{11-9}} =[/latex][latex]\frac{5^{2}}{3^{2}} - \frac{1}{3^{2}} = \frac{25-1}{9} = \frac{24}{9} =\frac{8}{3} [/latex]