7x^2-12|x|+5=0Решите ||-это модуль

[latex]7 x^{2} -12x+5=0[/latex] a=7  k=-6  c=5 [latex] D_{1} = k^{2} -ac=36-35=1[/latex] [latex] x_{1} = \frac{-k- \sqrt{ D_{1} } }{a} = \frac{6-1}{7} = \frac{5}{7} [/latex] [latex] x_{2} = \frac{-k+ \sqrt{ D_{1} } }{a} = \frac{6+1}{7} = \frac{7}{7} =1[/latex] Ответ:[latex] \frac{5}{7} [/latex] и 1