8^x - 3*4^x+ (9*4^x - 288)/2^x -9 ≤ 32найти все корни

2^3x-3*2^2x +(9*2^2x-288)/(2^x-9) -32≤0 2^x=a a³-3a²+(9a²-288)/(a-9)-32≤0 (a^4-9a³-3a³+27a²+9a²-288-32a+288)/(a-9)≤0 (a^4-12a³+36a²-32a)/(a-9)≤0 a(a³-12a²+36a-32)/(a-9)≤0 a[a²(a-2)-10a(a-2)+16(a-2))/(a-9≤0 a(a-2)(a²-10a+16)/(a-9)≤0 a(a-2)[a(a-2)-8(a-2)]/(a-9)≤0 a(a-2)(a-2)(a-8)/(a-9)≤0 a(a-2)²(a-8)/(a-9)≤0        _           +                +                _              + ----------[0]--------[2]------------[8]--------------(9)------------- a≤0⇒2^x≤0 нет решения a=2⇒2^x=2⇒x=1 8≤a<9⇒8<2^x<9⇒3≤x