Дано;BC=17,AC=8 Найти Sin

AB=[latex] \sqrt{17^{2}- 8^{2} } [/latex]=15 SinC= [latex] \frac{AB}{BC} [/latex]=[latex] \frac{15}{17} [/latex] SinB= [latex] \frac{AC}{BC} [/latex]=[latex] \frac{8}{17} [/latex] CosC= [latex] \frac{AC}{BC} [/latex]=[latex] \frac{8}{17} [/latex] CosB= [latex] \frac{AB}{BC} [/latex]=[latex] \frac{15}{17} [/latex] TgB=  [latex] \frac{AC}{AB} [/latex]=[latex] \frac{8}{15} [/latex]