Дополните схемы уравнений реакций,напишите ионные уравнения в полном и сокращенном виде.HNO3+Fe(OH)3MgO+HClZn+H2So4CuBr2+NaOh

[latex]3HNO_{3} + Fe(OH)_{3} = Fe(NO_{3})_{3} +3H_{2} O[/latex] [latex]3H ^+ + 3(NO_{3})^- + Fe ^{3+}+3OH^- = Fe^{3+} +3(NO_{3})^{-} +3H_{2} O[/latex] [latex]3H ^+ +3OH^- = 3H_{2} O[/latex] [latex]MgO +2HCl = MgCl_{2} + H_{2}O[/latex] [latex]Mg^{2+} +O ^{2-} +2H ^{+}+2Cl ^{-} = Mg^{2+} + 2Cl^{-} + H_{2}O[/latex] [latex]O ^{2-} +2H ^{+} =H_{2}O[/latex] [latex]Zn + H_{2} SO_{4} = ZnSO_{4} + H_{2}[/latex] [latex]Zn ^{0} + 2H ^{+} +SO_{4} ^{2-} = Zn ^{2+} + SO_{4}^{2-} + H_{2} ^{0}[/latex] [latex]Zn ^{0} + 2H ^{+} = Zn ^{2+}+H_{2} ^{0} [/latex] [latex]CuBr_{2} + 2NaOH = Cu(OH)_{2} + 2NaBr[/latex] [latex]Cu^{2+} +2Br^{-} + 2Na^+ + 2OH^- = Cu(OH)_{2} + 2Na^++2Br^{-}[/latex] [latex]Cu^{2+} + 2OH^- = Cu(OH)_{2}[/latex]