G(x)=√x^2-1 найти g'0 и g'(-2)

тогда g'(x) = 1/(2[latex] \sqrt{x^2-1} [/latex])*2x = x/[latex] \sqrt{x^2-1} [/latex] g'(0) = 0 g'(-2) = -2/[latex] \sqrt{3} [/latex]