[latex]\frac{1}{6 \sqrt{32} } - \frac{6* \sqrt{32}+ \frac{1}{8} }{6* \sqrt{32}* \frac{1}{8 } } [/latex]

Question

[latex]\frac{1}{6 \sqrt{32} } - \frac{6* \sqrt{32}+ \frac{1}{8} }{6* \sqrt{32}* \frac{1}{8 } } [/latex]

Алгебра

Гость

Ответ(ы) на вопрос:

Accepted Answer

[latex] \frac{1}{6 \sqrt{32} } - \frac{6 \sqrt{32}+ \frac{1}{8} }{6 \sqrt{32} * \frac{1}{8} } = \frac{ \frac{1}{8} -( 6 \sqrt{32}+ \frac{1}{8})}{6 \sqrt{32}* \frac{1}{8} } = \\ \\ =\frac{ \frac{1}{8} - 6 \sqrt{32}- \frac{1}{8}}{6 \sqrt{32}* \frac{1}{8} } = \frac{- 6 \sqrt{32}}{6 \sqrt{32}* \frac{1}{8} } = \frac{-1}{ \frac{1}{8} } = \\ \\ = -1 * \frac{8}{1} = -8[/latex]