Lim x- (-3 ) 3+x/x^2-9

[latex] \lim_{n \to \ -3} \frac{3+x}{ x^{2} -9} = \lim_{n \to \--3} \frac{3-3}{(-3) ^{2}-9 } = \frac{0}{0} \lim_{n \to \ -3} \frac{3+x}{(x-3)*(x+3)} = \lim_{n \to \ -3} \frac{1}{x-3}= -\frac{1}{6} [/latex]