Log1/3 (1+log3(2^x-7))=-1 решите плиз

ОДЗ {2^x-7>0⇒2^x>7⇒x>log(2)7 {1+log(3)(2^x-7))>0⇒log(3)(2^x-7)>-1⇒2^x-7>1/3⇒2^x>22/3⇒x>log(2)22/3 x∈(log(3)22/3;∞) 1+log(3)(2^x-7)=3 log(3)(2^x-7)=2 2^x-7=9 2^x=16 x=4