M(mg)=3 гр Hcl m(H2)=?

   3 г                                                             Х г    Mg        +        2HCl      =      MgCl2     +    H2n = 1 моль                                               n = 1 мольМ = 24 г/моль                                          М = 2 г/мольm = 24 г                                                   m = 2 г3 г Mg      -    Х г Н224 г Mg   -    2 г Н2m(H2) = 3 * 2 / 24 = 0,25 г