Найдите корень уравнения  (1/7)^2x-12= 1/49

[latex](\frac17)^{2x-12}=\frac1{49}[/latex] [latex](\frac17)^{2x-12}=(\frac1{7})^2\\ 2x-12=2\\2x=2+12\\2x=14\\x=14:2\\x=7 [/latex]