Найдите корни и промежуток [latex]3x^2-10x+3\ \textgreater \ 0 [/latex]

[latex]1)\ 3 x^{2} -10x+3=0 \\ D=10^2-4*3*3=100-36=64=8^2 \\ \\ x_1= \frac{10+8}.{2*3} \frac{18}{6} =3 \\ \\ x_2=\frac{10-8}{2*3}= \frac{1}{3} \\ \\ \\ 2)\ 3 x^{2} -10x+3\ \textgreater \ 0 \\ \\ +++( \frac{1}{3} )---(3)+++\ \textgreater \ x \\ \\ x\in (-\infty;\frac{1}{3})\ U\ (3;+\infty)[/latex]