Найдите значения 3(2^2+1)(2^4+1)(2^8+1)(2^16+1) - 2^32

[latex]3( 2^{2} +1)( 2^{4} +1)( 2^{8} +1)( 2^{16} +1)- 2^{32} =[/latex] [latex]= \frac{3( 2^{2}-1)( 2^{2} +1)( 2^{4} +1)( 2^{8} +1)( 2^{16} +1)}{( 2^{2}-1)} - 2^{32} =[/latex] [latex]= \frac{3( 2^{4}-1)( 2^{4} +1)( 2^{8} +1)( 2^{16} +1)}{3} - 2^{32}=[/latex] [latex]= ( 2^{8}-1)( 2^{8} +1)( 2^{16} +1)- 2^{32}=( 2^{16}-1)( 2^{16} +1)-2^{32}=2^{32}-1-2^{32}=-1[/latex]