Найти область определения функции y=√(log2 (x-6))

[latex]y=\sqrt{\log_2(x-6)}, \\ \left \{ {{\log_2(x-6)\geq0,} \atop {x-6\ \textgreater \ 0,}} \right. \left \{ {{x-6\geq1,} \atop {x-6\ \textgreater \ 0,}} \right. \left \{ {{x\geq7,} \atop {x\ \textgreater \ 6,}} \right. \\ x\geq7, \\ x\in(7;+\infty).[/latex]