Найти первые семь членов числовой последовательности

х1 = 1 х2 = 2*2/(2+1) -1= 4/3 -1 = 1/3 х3 = 2*3/(3+1) - 1/3 = 6/4 -1/3 = 3/2 -1/3 = 7/6 х4 = 2*4/(4+1) - 7/6 = 8/5 - 7/6 = 13/30 х5= 2*5/(5+1) - 13/30= 10/6 - 13/30= 5/3 - 13/30 = 37/30 х6 = 2*6/(6+1) - 37/30 = 12/7 - 37/30 = = 101/210 х7 = 2*7/(7+1) - 101/210 = 14/8 - 101/210 = 7/4 - 101/210 = 533/420