Обчислити інтергал ∫_1^3∫(2/х^3 -6)dx

[latex]\displaystyle \int\limits^3_1 {\bigg( \frac{2}{x^3} -6\bigg)} \, dx =\bigg(- \frac{1}{x^2} -6x\bigg)\bigg|^3_1=- \frac{1}{x^2} \bigg|^3_1-6x\bigg|^3_1=\\ \\ \\ =- \frac{1}{3^2} + \frac{1}{1^2} -6\cdot 3+6\cdot 1= -\frac{1}{9} +1-18+6=- \frac{100}{9} [/latex]