∫от -2 до 1 (3x^2-6x+1)dx

[latex] \int\limits^1_{-2} {(3x^2-6x+1)} \, dx =(3*\frac{x^3}{3}-6*\frac{x^2}{2}+x)|^{^{^1}}}_{_{_{_{-2}}}}=(x^3-3x^2+x)|^{^{^1}}}_{_{_{_{-2}}}}= \\=(1-3+1)-(-8-12-2)=-1+22=21[/latex]