Po algebre pomogite pojaluista

[latex] \frac{x^2-4x+1}{x^2-2(2+\sqrt3)x+7+4\sqrt3} =\frac{(x-(2-\sqrt3))(x+2+\sqrt3)}{(x-(2+\sqrt3))^2}=\frac{(x-2+\sqrt3)(x+2+\sqrt3)}{(x-2-\sqrt3)^2}\\\\a)\; x^2-4x+1=0\; ,\; D/4=2^2-1=3\; ,\; \; x_{1,2}=2\pm \sqrt3\\\\b)\; x^2-2(2+\sqrt3)x+(7+4\sqrt3)=0\; ,\\\\D/4=(2+\sqrt3)^2-(7+4\sqrt3)=4+3+4\sqrt3-7-4\sqrt3=0\; ,\\\\x_{1,2}=2+\sqrt3\\\\c)\; ax^2+ 2px+c=0\; ,\; \; \; D/4=p^2-ac\; ,\; \; x_{1,2}=\frac{-p\pm \sqrt{D/4}}{a}[/latex]