Помогите пожалуйста Мне срочно нужно с 4.36

a)(a-12)/(2a-8)+a/(a-4)=(a-12)/2(a-4)+a/(a-4)=(a-12+2a)/2(a-4)=(3a-12)/2(a-4)=3(a-4)/2(a-4)=3/2=1,5б)(x-1)/(3x-12)-(x-2)/(2x-8)=(x-1)/3(x-4)-(x-2)/2(x-4)=(2(x-1)-3(x-2))/6(x-4)=(2x-2-3x+6)/6(x-4)=(-x+4)/(x-4)=-(x-4)/6(x-4)=-1/6в)(y-27)/(6-2y)+4y/(3-y)=(y-27)/2(3-y)+4y/(3-y)=(y-27+8y)/2(3-y)=(9y-27)/2(3-y)=9(y-3)/2(y-3)=-9(3-y)/2(3-y)=-9/2=-4,5г)(c-2)/(6c+4)-(c-6)/(15c+10)=(c-2)/2(3c+2)-(c-6)/5(3c+2)=(5(c-2)-2(c-6))/10(3c+2)=(5c-10-2c+12)/10(3c+2)=(3c+2)/10(3c+2)=1/10=0,1