ПОМОГИТЕ ПОЖАЛУЙСТА. 2/x-3 - x/x-3 = 4x/x^2 - 9

[latex] \frac{2}{x-3} [/latex]-[latex] \frac{x}{x-3} [/latex]=[latex] \frac{4x}{ x^{2} -9} [/latex] [latex] \frac{2-x}{x-3} [/latex]-[latex] \frac{4x}{ x^{2} -9} [/latex]=0 [latex] \frac{(x+3)(2-x)-4x}{(x-3)(x+3)} [/latex]=[latex] \frac{2x- x^{2} +6-3x-4x}{(x-3)(x+3)} [/latex]=[latex] \frac{-5x- x^{2} +6}{(x-3)(x+3)} [/latex]=[latex] \frac{- x^{2} -5x+6}{(x-3)(x+3)} [/latex] По Th Виета:[latex] \left \{ {{ x_{1} * x_{2} =c=6} \atop { x_{1}+ x_{2} =-b=5 }} \right. [/latex] [latex] \left \{ {{ x_{1} =2} \atop { x_{2}=3}} \right. [/latex] [latex] \frac{-(x-3)(x-2)}{(x-3)(x+3)} [/latex]=-[latex] \frac{x-2}{x+3} [/latex]