Помогите пожалуйста ∫ от 0 до 12 dx/√9*12^2-5*12x 

[latex] \int\limits^{12}_0 \frac{dx}{\sqrt{9\cdot 12^2-5\cdot 12x}}= \int\limits^{12}_0 \frac{dx}{\sqrt{12}\cdot \sqrt{156-5x}} =\frac{1}{\sqrt{12}}\cdot (-\frac{1}{5})\cdot 2\sqrt{156-5x}\left |_0^{12}=[/latex] [latex]=- \frac{1}{5\sqrt3} (\sqrt{156-5\cdot 12}-\sqrt{156-5\cdot 0})=\\\\=-\frac{1}{5\sqrt3}(\sqrt{96}-\sqrt{156})=-\frac{1}{5\sqrt3}(4\sqrt6-2\sqrt{39})=\frac{2}{5\sqrt3}(\sqrt{39}-2\sqrt6) [/latex]