Помогите пожалуйста решить. напишите решение пожалуйста даю 99 б

1 log(3)135/log(15)3=log(3)135:log(3)3/log(3)15=(log(3)5+3):1/(log(3)5+1)= =(log(3)5+3)*(log(3)5+1) log(3)5/log(405)3=log(3)5 :log(3)3/log(3)405=log(3)5:1/(log(3)5+4)= =log(3)5*(log(3)5+4) (log(3)5+3)*(log(3)5+1) -log(3)5*(log(3)5+4)= =log²(3)5+log(3)5+3log(3)5+3-log²(3)5-4log(3)5=3 2 3+log(12)27=3+log(27)/log(3)12=3+3/(2log(3)2+1)= =(6log(3)2+3+3)/(2log(3)2+1)=6(log(3)2+1)/(2log(3)2+1) 3-log(12)27=3-log(27)/log(3)12=3-3/(2log(3)2+1)=(6log(3)2+3-3)/(2log(3)2+1) =6log(3)2/(2log(3)2+1) 6(log(3)2+1)/(2log(3)2+1) :6log(3)2/(2log(3)2+1)= =6(log(3)2+1)/(2log(3)2+1)* (2log(3)2+1)/6log(3)2=6(log(3)2+1)/6log(3)2= =(log(3)2+1)/log(3)2= log(6)16=log(3)16/log(3)6=4log(3)2/(log(3)2+1)  (log(3)2+1)/log(3)2*4log(3)2/(log(3)2+1)=4