Помогите решить №142

[latex]1) log_{ \sqrt{3}} \frac{1}{3 \sqrt[3]{3}}= log_{ \sqrt{3}} \frac{1}{ 3^{ \frac{4}{3} } }= log_{ 3^{ \frac{1}{2}}} 3^{- \frac{4}{3}}=- \frac{4}{3}: \frac{1}{2} log_{3}3=- \frac{4}{3}*2=- \frac{8}{3}; [/latex] [latex] log_{ \sqrt{5}} \frac{1}{25 \sqrt[4]{5}}= log_{ \sqrt{5}} \frac{1}{ 5^{ \frac{9}{4}}}= log_{ 5^{ \frac{1}{2}}} 5^{- \frac{9}{4}}=- \frac{9}{4}: \frac{1}{2} log_{5}5=- \frac{9}{4}*2=- \frac{9}{2}; \\ [/latex] [latex]3) 2^{2- log_{2}5}= \frac{ 2^{2}}{ 2^{ log_{2}5}}= \frac{4}{5}; \\ [/latex] [latex]4) 3,6^{ log_{3,6}10+1}= 3,6^{ log_{3,6}10}*3,6=10*3,6=36; \\ [/latex] [latex]5) 2 log_{5} \sqrt{5}+3 log_{2}8=2 log_{5} 5^{ \frac{1}{2}}+3*3=2* \frac{1}{2}+9=1+9=10; \\ [/latex] [latex]6) log_{2} log_{2} log_{2} 2^{16}= log_{2} log_{2} 16=log_{2}4=2. [/latex]