Помогите решить, пожалуйста [latex] \left \{ {{ \sqrt{7-6x-y^{2} }=y+5 } \atop {y=x-1}} \right. [/latex]

[latex] \left \{ {{ \sqrt{7-6x-y^2} =y+5} \atop {y=x-1}} \right. [/latex] ОДЗ: [latex]y \geq -5[/latex] [latex] \left \{ {{ \sqrt{7-6x-(x-1)^2} =x-1+5} \atop {y=x-1}} \right. [/latex] [latex]\left \{ {{ \sqrt{7-6x-x^2+2x-1} =x+4} \atop {y=x-1}} \right. [/latex] [latex]\left \{ {{ \sqrt{-x^2-4x+6} =x+4} \atop {y=x-1}} \right. [/latex] ОДЗ: [latex]x+4 \geq 0[/latex]           [latex]x \geq -4[/latex] [latex]\left \{ {{ (\sqrt{-x^2-4x+6})^2=(x+4)^2} \atop {y=x-1}} \right. [/latex] [latex]\left \{ {{ {-x^2-4x+6}= x^{2} +8x+16} \atop {y=x-1}} \right. [/latex] [latex]\left \{ {{ {2x^2+12x+10}=0} \atop {y=x-1}} \right. [/latex] [latex]\left \{ {{ {x^2+6x+5}=0} \atop {y=x-1}} \right. [/latex] [latex]x^2+6x+5=0[/latex] [latex]D=6^2-4*1*5=36-20=16[/latex] [latex]x_1= \frac{-6+4}{2} =-1[/latex] [latex]x_2= \frac{-6-4}{2} =-5[/latex] - не подходит [latex] \left \{ {{x=-1} \atop {y=x-1}} \right. [/latex] [latex] \left \{ {{x=-1} \atop {y=-2}} \right. [/latex] Ответ: [latex](-1;-2)[/latex]