Помогите решить приложенные примеры (50 баллов)

1) sin(2(π/6  +  x/4)) - sin(2*(π/4))=0 sin(π/3 + x/2) - sin(π/2)=0 sin(π/3 + x/2)=1 π/3 + x/2=π/2 + 2πk, k∈Z x/2= π/2 - π/3 + 2πk x/2= [(3π-2π)/6] + 2πk x/2= π/6 + 2πk x= π/3 + 4πk, k∈Z 2) f(x- π/4) =sin 2(x - π/4) = sin(2x - π/2)= sin(-(π/2 - 2x))= = -sin(π/2 - 2x)= - cos2x.