Помогите решить пример sqrt(11-6sqrt2)+sqrt2

[latex] \sqrt{11-6 \sqrt{2} } + \sqrt{2}=3 1. \sqrt{11-6 \sqrt{2} } = \sqrt{11-2*3* \sqrt{2} } = \sqrt{9+2-2*3* \sqrt{2} } =[/latex] [latex]= \sqrt{ 3^{2}-2*3* \sqrt{2} +( \sqrt{2} )^{2} } = \sqrt{(3- \sqrt{2} )^{2} } =|3- \sqrt{2} |=3- \sqrt{2} . 3- \sqrt{2+ \sqrt{2} } =3[/latex]