Помогите решить систему уравнений(10кл)

[latex] \left \{ {{x-2y=8} \atop {x^2+2y^2=22}} \right. \\ \\ 1. \\ x-2y=8 \\ x=8+2y \\ \\ 2. \\ (8+2y)^2+2y^2=22 \\ 64+32y+4y^2+2y^2-22=0 \\ 6y^2+32y+42=0|:2 \\ 3y^2+16y+21=0 \\ D=256-4*3*21=256-252=4 \\ \\ x1= \frac{-16+2}{6}= \frac{-14}{6} =- \frac{7}{3} =-2 \frac{1}{3} \\ \\ x2= \frac{-16-2}{6} =-18/6=-3 \\ \\ 3. \\ \\ \left \{ {{x=-2 \frac{1}{3} } \atop {y=3 \frac{1}{3} }} \right. \\ \left \{ {{x=-3} \atop {y=2}} \right. [/latex] Ответ: (-2 1/3; 3 1/3)(-3;2)